Rectangle calculator

problem

Find area $ A $ of a rectangle if side $a = 6$ and side $b = \frac{ 9 }{ 2 }$.

solution

$$ A = 27 $$

explanation

To find area $ A $ use formula:

$$ A = a \cdot b $$

After substituting $ a = 6 $ and $ b = \frac{ 9 }{ 2 } $ we have:

$$ A = 6 \cdot \frac{ 9 }{ 2 } $$$$ A = 27 $$

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Script name : rectangle-calculator

Form values: 4 , 6 , 9/2 , g , Find area A of a rectangle if side a = 6 and side b = 9/2 . , , ,

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Select the missing value after entering two rectangle elements (length, width, diagonal, area, or perimeter). The calculator will provide you a step-by-step solution to the given problem.
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Input what to find:
Input any two known values of a rectangle
calculator works with decimals, fractions and square roots ( to input $ \color{blue}{\sqrt{2}} $ type $ \color{blue}{\text{r2}} $)
$ a $
=
$ b $
=
$ d $
=
AreaA
=
PerimP
=
 
 
 
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EXAMPLE PROBLEMS
example 1:ex 1:
Find the area of the rectangle whose sides are $ a = \dfrac{5}{3} $ and $ b = \dfrac{3}{2} $.
example 2:ex 2:
If the diagonal is 9 cm and one side is 5 cm, find the area of a rectangle.
example 3:ex 3:
A rectangle has an area of 18 cm2 and a side length of 16/5cm. Determine the perimeter.
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TUTORIAL

Rectangle calculations

This calculator uses the following formulas to find the missing values of a rectangle:

Area: $$ A = a \cdot b $$ rectangle
Perimeter: $$ P = 2a + 2b $$
Diagonal: $$ d^2 = a^2 + b^2 $$

Example 01 :

What is the area of a rectangle with a base of 12 cm and a height of 3/2 cm?

Solution:

base $ a = 6 $

height $ b = \dfrac{9}{2} $

$$ \color{blue}{A = a \cdot b} = 6 \cdot \frac{9}{2} = \frac{54}{2} = 27 $$

Example 02 :

What is the perimeter of a rectangle with a length of 7/2cm and a width of 5/2cm?

Solution:

length $ a = \dfrac{7}{2} \, cm $

width $ b = \dfrac{5}{2} \, cm $

$$ \color{blue}{P = 2a + 2b} = 2 \cdot \frac{7}{2} + 2 \cdot \dfrac{5}{2} = 7 + 5 = 12 $$

Example 03 :

The area of a rectangle is 42 cm2. Find its perimeter if the width is 7cm.

Solution:

We'll need two steps to solve this one:

Step 1: find length ( b ):

width $ a = 7 cm $

area: $ A = 42 cm $

$$ \begin{aligned} A & = a \cdot b \\[ 1 em] 42 & = 7 \cdot b \\[ 1 em] b & = \frac{42}{7}\\[ 1 em] b & = 6 \\[ 1 em] \end{aligned} $$

Step 2: find perimeter ( P )

width $ a = 7 cm $

length $ b = 6 cm $

$$ \begin{aligned} P & = 2a + 2b \\[ 1 em] P & = 2 \cdot 7 + 2 \cdot 6 \\[ 1 em] P & = 14 + 12 \\[ 1 em] P & = 28 \, cm^2 \\[ 1 em] \end{aligned} $$

Example 04 :

What is the diagonal of a rectangle if the perimeter is P = 11/2 cm and a width is a = 3/2 cm ?

Solution:

Step 1: find length ( b ):

width $ a = \dfrac{3}{2} cm $

perimeter: $ P = \dfrac{11}{2} cm $

$$ \begin{aligned} P & = 2a + 2b \\[ 1 em] \frac{11}{2} & = 2 \cdot \frac{3}{2} + 2b \\[ 1 em] \frac{11}{2} & = 3 + 2b \\[ 1 em] 2b &= \frac{11}{2} - 3 \\[1 em] 2b &= \frac{5}{2} \\[1 em] b &= \frac{5}{4} \end{aligned} $$

Step 2: find diagonal ( d )

width $ a = \dfrac{3}{2} cm $

length $ b = \dfrac{5}{4} cm $

$$ \begin{aligned} d^2 & = a^2 + b^2 \\[ 1 em] d^2 & = \left( \frac{3}{2} \right)^2 + \left( \frac{5}{4} \right)^2 \\[ 1 em] d^2 & = \frac{9}{4} + \frac{25}{16} \\[ 1 em] d^2 & = \frac{61}{16} \\[ 1 em] d & = \frac{\sqrt{61}}{4} \end{aligned} $$
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