This calculator finds the square root, modulus, inverse, conjugate and converts complex numbers to polar form. The solver explains each operation in detail, step by step.
solution
The modulus of $ z $ is:
$$ |z| = 3 \sqrt{ 5 }$$explanation
To find modulus of a complex number $ z = a + bi $ we use formula:
$$ |z| = \sqrt{a^2 + b^2} $$In this example we have $ a = 6 $ and $ b = 3 $ so:
$$ \begin{aligned}|z| &= \sqrt{ 6^2 + 3^2 } \\[1 em]|z| &= \sqrt{ 36 + 9 } \\[1 em]|z| &= \sqrt{ 45 } \\[1 em]|z| &= 3 \sqrt{ 5 } \\[1 em] \end{aligned} $$This calculator performs five operations on a single complex number: modulus, conjugate, inverse, roots and polar form. We will demonstrate how to solve each of these problems using five basic examples.
The modulus or magnitude of a complex number (denoted by |z|), is the distance between the origin and that number.
If the z = a + bi is a complex number than the modulus is
$$ \color{blue}{|z| = \sqrt{a^2 + b^2}} $$Example 01: Find the modulus of z = 6 + 3i.
In this example a = 6 and b = 3, so the modulus is:
$$ \begin{aligned} | z | &= \sqrt{ a^2 + b^2} = \sqrt{6^2 + 3^2} = \\[1 em] &= \sqrt{36 + 9} = \sqrt{45} = \\[1 em] &= \sqrt{9 \cdot 5} = 3 \sqrt{5} \end{aligned} $$To find the complex conjugate of a complex number, we just need to change the sign of the imaginary part.
The conjugate of z = a + bi, is z=a – bi
Example 02: The complex conjugate of z=3+4i is z=3-4i.
Example 03: The conjugate of z=-4i is z=4i.
Example 04: The conjugate of z=15 is z=15, too.
The inverse or reciprocal of a + bi is
$$ \color{blue}{ \frac{1}{a + b\,i}} $$Here is an example of how to find the inverse.
Example 06: Find the inverse of the number z=4+3i.
$$ \begin{aligned} \frac{1}{z} &= \frac{1}{4+3i} = \frac{1}{4+3i} \cdot \frac{4-3i}{4-3i} = \\[1 em] &= \frac{4-3i}{(4+3i)(4-3i)} = \frac{4-3i}{4^2 - (3i)^2} = \\[1 em] &= \frac{4-3i}{16+9} = \frac{4-3i}{25} = \frac{4}{25} - \frac{3}{25} i \end{aligned} $$The polar form of a complex number z = a + ib is given as:
$$ z = |z| ( \cos \alpha + i \sin \alpha) $$Example 05: Express the complex number z = 2 + i in polar form.
To find a polar form, we need to calculate |z| and α using formulas in the above image.
$$ |z| = \sqrt{2^2 + 1^2} = \sqrt{5}$$ $$ \tan \alpha = \dfrac{b}{a} = \dfrac{1}{2} \implies \alpha = \tan^{-1}\left(\dfrac{1}{2}\right) \approx 27^{o} $$So, the polar form is:
$$ z = \sqrt{5} \left( \cos 27^o + i \sin27^o \right) $$1. How to find conjugate and modulus ?
2. Polar form of a complex number — video tutorial with solved examples.