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Trinomials Factoring Calculator

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This calculator factors quadratic trinomials of the form ax2+bx+c using the AC method and a formula ax2+bx+c=a(x-x1)(x-x2), where x1 and x2 are solutions of a quadratic equation. Calculator shows all the work and provides detailed explanation for each step.

Factor trinomial $$ \color{blue}{ 25x^2-4 } $$

solution

The factored form is $$ \color{blue}{ 25x^2-4 = \left(5x+2\right)\left(5x-2\right) } $$

explanation

We can see that both terms are perfect squares. $ 25x^2 = ( 5 x )^2 ~~ \text{and} ~~ 4 = 2 ^2 $

so we can use the difference of squares formula:

$$ a^2 - b^2 = (a - b)(a + b) $$ $$ 25x^{2}-4 = \left(5x+2\right) \left(5x-2\right) $$

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Script name : factoring-trinomials-calculator

Form values: 25 , 1 , 0 , 2 , 4 , g , Factor trinomial 25x^2-4 , Factor 25x^2-4

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Factoring quadratic trinomials
Factors trinomials of the form ax2+bx+c.
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Examples
ex 1:
Factor 16x2 + 16x + 1.
ex 2:
Write trinomial 2x2-5x-3 in factored form.
ex 3:
Factor 6x2 + 13x - 5
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TUTORIAL

Polynomial Factoring Techniques

This calculator factors trinomials of the form $ ax^2 + bx + c $ using the methods listed below.

1. Factoring perfect square trinomial

2. Factor if leading coefficient $ a = 1 $

3. Factor if leading coefficient $ a \ne 1 $

4. Special cases ( $ b = 0 $ ) or ( $ a = 0 $ )

Method 1 : Factoring perfect square trinomial

Example 01: Factor $ 4a^2 - 12a + 9 $

Step1: Verify that both the first and third terms are perfect squares.

$4a^2$ is perfect square because $4a^2 = \left(\color{blue}{2a}\right)^2$

$9$ is perfect square because $9 = \left(\color{red}{3}\right)^2 $

Step2: Check if middle term is twice the product of $ \color{blue}{2a} $ and $ \color{red}{3} $

$$ \text{middle term} = 12a = 2 \cdot \color{blue}{2a} \cdot \color{red}{3} $$

Step3: Put $ \color{blue}{2a} $ and $ \color{red}{3}$ inside parentheses. Because the middle term's coefficient is negative, we'll insert a minus sign inside parenthesis.

$$ 4a^2 - 12a + 9 = ( \color{blue}{2a} - \color{red}{3} )^2 $$

Method 2 : Leading coefficient $ a = 1 $

In this case, the trinomial has the following form $ x^2 + bx + c $.

Example 02: Factor $ x^2 + 7x + 10 $

To factor this trinomial we need to find two integers ( $p$ and $q$ ) such that $ p + q = b $ and $ p \cdot q = c $.

In this example $ p + q = 7 $ and $p \cdot q = 10$

After some trials and errors we get $ p = 2 $ and $ q = 5 $

The factored form is

$$ x^2 + 7x + 10 = ( x + p)(x + q) = (x + 2)(x + 5) $$

Method 4 : Special Cases

Example 04: Factor $ 3x^2 + 5x $

This is special case where $c = 0$.

To solve this one we just need to factor $x$ out of $ 3x^2 + 5x $

$$ 3x^2 + 5x = x ( 3x + 5) $$

Example 05: Factor $ 25x^2 - 4 $

This is special case where $b = 0$.

We'll need to use the difference of squares formula to factor this one.

$$ 25x^2 - 4 = (5x)^2 - 2^2 = (5x-2)(5x+2) $$

Method 3 : Leading coefficient $ a \ne 1 $

In this case, the trinomial has the following form: $ ax^2 + bx + c $.

Example 03: Factor $ 3x^2 - 5x + 2 $

Step 1: Identify constants $a$ , $ b $ and $c$

$$ a = 3, b = -5 , c = 2 $$

Step 2: Find out two numbers ( $p$ and $q$) that multiply to $ a \cdot c = 6 $ and add up to $ b = -5 $.

After some trials and errors we get $ \color{blue}{p = -2} $ and $ \color{red}{q =-3} $

Step 3:Replace middle term ( $ -5x $ ) with $ \color{blue}{-2}x \color{red}{-3}x $

$$ 3x^2 - 5x + 2 = 3x^2 - 2x - 3x + 2 $$

Step 4:Factor out x from the first two terms and -1 from the last two terms.

$$ \begin{aligned} 3x^2 - 5x + 2 &= 3x^2 - 2x - 3x + 2 = \\\\ &= x(3x-2) -1(3x-2) = \\\\ &=(x - 1)(3x-2) \end{aligned} $$
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