Compound Interest is calculated on the initial payment and also on the interest of previous periods.
Example: Suppose you give \$100 to a bank which pays you 10% compound interest at the end of every year. After one year you will have \$100 + 10% = \$110, and after two years you will have \$110 + 10% = \$121.
Problem:
If you deposit $4500 into an account paying 7% annual interest compounded semi anualy , how much money will be in the account after 9 years?
Result:
The amount is $8358.7 and the interest is $3858.7.
Explanation:
STEP 1: To find amount we use formula:
$$ A = P \left( 1 + \frac{r}{n} \right)^{\Large{n \cdot t}} $$ |
A = total amount P = principal or amount of money deposited, r = annual interest rate n = number of times compounded per year t = time in years |
In this example we have
$$ P = \$4500 ~,~ r = 7 \% ~ , ~ n = 2 ~ \text{and} ~ t = 9 ~ \text{years}$$After plugging the given information we have
$$ \begin{aligned} A &= 4500 \left( 1 + \frac{ 0.07 }{ 2 } \right)^{\Large{ 2 \cdot 9 }} \\ A &= 4500 \cdot { 1.035 } ^ { 18 } \\ A &= 4500 \cdot 1.857489 \\ A &= 8358.7 \end{aligned}$$STEP 2: To find interest we use formula $ A = P + I $, since $ A = $8358.7 $ and $ P = $4500 $ we have:
$$ \begin{aligned} A &= P + I \\ 8358.7 &= 4500 + I \\ I &= 8358.7 - 4500 \\ I &= 3858.7 \end{aligned}$$Share this result with others by using the link below.
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