Math Calculators, Lessons and Formulas

It is time to solve your math problem

mathportal.org

# Math formulas:Integrals of trigonometric functions

 0 formulas included in custom cheat sheet

### List of integrals involving trigonometric functions

 $$\int \sin x ~ dx = -\cos x$$
 $$\int \cos x ~ dx = \sin x$$
 $$\int \sin^2x ~ dx= \frac{x}{2}-\frac{1}{4}\sin(2x)$$
 $$\int \cos^2x ~ dx = \frac{x}{2}+\frac{1}{4}\sin(2x)$$
 $$\int \sin^3x ~ dx = \frac{1}{3}\cos^3x-\cos x$$
 $$\int \cos^3x ~ dx = \sin x - \frac{1}{3}\sin^3x$$
 $$\int \frac{dx}{\sin x} = \ln\left| \tan \frac{x}{2} \right|$$
 $$\int \frac{dx}{\cos x} = \ln\left| \tan \left(\frac{x}{2} + \frac{\pi}{4}\right)\right|$$
 $$\int \frac{dx}{\sin^2x} = -\cot x$$
 $$\int \frac{dx}{\cos^2x} = \tan x$$
 $$\int \frac{dx}{\sin^3x} = -\frac{\cos x}{2\cdot \sin^2x} + \frac{1}{2}\ln\left|\tan\frac{x}{2}\right|$$
 $$\int \frac{dx}{\cos^3x} = \frac{\sin x}{2\cdot \cos^2x} + \frac{1}{2}\ln\left|\tan\left(\frac{x}{2}+\frac{\pi}{2}\right)\right|$$
 $$\int \sin x \cdot \cos x dx = - \frac{1}{4}\cos(2x)$$
 $$\int \sin^2x \cdot \cos x dx = \frac{1}{3}\sin^3x$$
 $$\int \sin x \cdot \cos^2x dx = -\frac{1}{3}\cos^3x$$
 $$\int \sin^2x \cdot \cos^2x dx = \frac{x}{8}-\frac{1}{32}\sin(4x)$$
 $$\int \tan x~dx = -\ln|\cos x|$$
 $$\int \frac{\sin x}{\cos^2x}dx = \frac{1}{\cos x}$$
 $$\int \frac{\sin^2x}{\cos x} dx = \ln \left| \tan\left( \frac{x}{2}+\frac{\pi}{4}\right ) \right| - \sin x$$
 $$\int \tan^2x~dx = \tan x-x$$
 $$\int \cot x~dx =\ln|\sin x|$$
 $$\int \frac{\cos x}{\sin^2x}dx=-\frac{1}{\sin x}$$
 $$\int \frac{\cos^2x}{\sin x}dx = \ln\left|\tan\frac{x}{2}\right| + \cos x$$
 $$\int \cot^2x~dx = -\cot x - x$$
 $$\int \frac{dx}{\sin x \cdot \cos x} = \ln|\tan\,x|$$
 $$\int \frac{dx}{\sin^2x \cdot \cos x} = -\frac{1}{\sin x} + \ln\left|\tan\left(\frac{x}{2} + \frac{\pi}{4}\right)\right|$$
 $$\int \frac{dx}{\sin x \cdot \cos^2x}=\frac{1}{\cos x}+\ln\left|\tan\frac{x}{2}\right|$$
 $$\int \frac{dx}{\sin^2x \cdot \cos^2x}=\tan x - \cot x$$
 $$\int \sin(mx)\cdot \sin(nx)~dx = -\frac{\sin(m+n)x}{2(m+n)} + \frac{\sin(m-n)x}{2(m-n)}, \quad m^2 \ne n^2$$
 $$\int \sin(mx)\cdot \cos(nx)~dx = -\frac{\cos(m+n)x}{2(m+n)} - \frac{\cos(m-n)x}{2(m-n)}, \quad m^2 \ne n^2$$
 $$\int \cos(mx)\cdot \cos(nx)~dx = \frac{\sin(m+n)x}{2(m+n)} + \frac{\sin(m-n)x}{2(m-n)}, \quad m^2 \ne n^2$$
 $$\int \sin x \cdot \cos^nx~dx = \frac{\sin^{n+1}x}{n+1}$$
 $$\int \sin^nx \cdot \cos\,x~dx = \frac{\sin^{n+1}x}{n+1}$$
 $$\int \arcsin x~dx = x\cdot \arcsin x + \sqrt{1-x^2}$$
 $$\int \arccos x~dx = x \cdot \arccos x - \sqrt{1-x^2}$$
 $$\int \arctan x ~dx = x \cdot \arctan x - \frac{1}{2}\ln(1+x^2)$$
 $$\int \mathrm{arccot}\,x~dx = x \cdot \mathrm{arccot}\,x + \frac{1}{2}\ln(1+x^2)$$