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• Mixed problems

# Mixed problems

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•  Question 1: 1 pts The following expression can be used to find the area of the shaded region shown on the picture. $$A=\left(12^{2}-6^{2}\pi\right)cm^{2}$$
•  Question 2: 1 pts The perimeter of the figure shown on the picture is $4 \pi cm.$
•  Question 3: 1 pts The perimeter of the figure shown on the picture is $$(16+3\pi)cm.$$
•  Question 4: 1 pts The following expression can be used to find the area of the shaded region shown on the picture. $$A=A_{\vartriangle}-A_{i}=\dfrac{6^{2}\sqrt{3}}{4}-\dfrac{\left(3\sqrt{3}\right)^{2}\pi \cdot 60^{\circ}}{360^{\circ}}=\dfrac{36\sqrt{3}}{4}-\dfrac{9\cdot 3\cdot \pi}{6}=9\cdot \left(\sqrt{3}-\dfrac{\pi}{2}\right)cm^{2}$$
•  Question 5: 2 pts Find the perimeter of the shaded figure shown on the picture.
$P=$
•  Question 6: 2 pts Find the area of the shaded figure shown on the picture.
 $A=\left(25-\dfrac{25\pi}{3}\right) cm^{2}$ $A=\left(50-\dfrac{\pi}{4}\right) cm^{2}$ $A=\left(75-\dfrac{25\pi}{4}\right) cm^{2}$ $A=\left(100-\dfrac{25\pi}{2}\right) cm^{2}$
•  Question 7: 2 pts Find the area of the shaded figure shown on the picture.
 $A=72cm^{2}$ $A=72\pi cm^{2}$ $A=36cm^{2}$ $A=36\pi cm^{2}$
•  Question 8: 2 pts Find the length of the broken line shown on the picture.
Length of the broken line $=$
•  Question 9: 3 pts Find the length of the broken line shown on the picture.
Length of the broken line $=$
•  Question 10: 3 pts Find the area of the shaded figure shown on the picture.
$A=$
•  Question 11: 3 pts If the area of rectangle shown on the picture is $32 cm^{2}$ then the area of the shaded figure shown on the picture is $A=4\cdot (2+\pi) cm^{2}.$
•  Question 12: 3 pts The following expression can be used to find the perimeter of shaded figure shown on the picture, if the length of the side of regular hexagon is 12cm. $P=\left (6\cdot 12+6\cdot \dfrac{6\pi \cdot 60^{\circ}}{180^{\circ}}\right)cm.$