Mixed problems

Question 1:
1 pts
The following expression can be used to find the area of the shaded region shown on the picture. $$A=\left(12^{2}-6^{2}\pi\right)cm^{2}$$
Question 2:
1 pts
The perimeter of the figure shown on the picture is $4 \pi cm.$
Question 3:
1 pts
The perimeter of the figure shown on the picture is $$ (16+3\pi)cm.$$

Question 4:

1 pts

The following expression can be used to find the area of the shaded region shown on the picture. $$ A=A_{\vartriangle}-A_{i}=\dfrac{6^{2}\sqrt{3}}{4}-\dfrac{\left(3\sqrt{3}\right)^{2}\pi \cdot 60^{\circ}}{360^{\circ}}=\dfrac{36\sqrt{3}}{4}-\dfrac{9\cdot 3\cdot \pi}{6}=9\cdot \left(\sqrt{3}-\dfrac{\pi}{2}\right)cm^{2}$$

Question 5:
2 pts
Find the perimeter of the shaded figure shown on the picture.

$P=$

Question 6:

2 pts

Find the area of the shaded figure shown on the picture.

	$A=\left(25-\dfrac{25\pi}{3}\right) cm^{2}$
	$A=\left(50-\dfrac{\pi}{4}\right) cm^{2}$
	$A=\left(75-\dfrac{25\pi}{4}\right) cm^{2}$
	$A=\left(100-\dfrac{25\pi}{2}\right) cm^{2}$

Question 7:
2 pts
Find the area of the shaded figure shown on the picture.

$A=72cm^{2}$

$A=72\pi cm^{2}$

$A=36cm^{2}$

$A=36\pi cm^{2}$
Question 8:
2 pts
Find the length of the broken line shown on the picture.

Length of the broken line $=$
Question 9:
3 pts
Find the length of the broken line shown on the picture.

Length of the broken line $=$
Question 10:
3 pts
Find the area of the shaded figure shown on the picture.

$A=$
Question 11:
3 pts
If the area of rectangle shown on the picture is $32 cm^{2}$ then the area of the shaded figure shown on the picture is $A=4\cdot (2+\pi) cm^{2}.$

Question 12:

3 pts

The following expression can be used to find the perimeter of shaded figure shown on the picture, if the length of the side of regular hexagon is 12cm. $P=\left (6\cdot 12+6\cdot \dfrac{6\pi \cdot 60^{\circ}}{180^{\circ}}\right)cm.$

Mixed problems

Triangle

Quadrilateral

Circle

Polygons

	$A=72cm^{2}$
	$A=72\pi cm^{2}$
	$A=36cm^{2}$
	$A=36\pi cm^{2}$