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Question 1:
1 pts
The following expression can be used to find the area of the shaded region shown on the picture. $$A=\left(12^{2}-6^{2}\pi\right)cm^{2}$$
Question 2:
1 pts
The perimeter of the figure shown on the picture is $4 \pi cm.$
Question 3:
1 pts
The perimeter of the figure shown on the picture is $$ (16+3\pi)cm.$$
Question 4:
1 pts
The following expression can be used to find the area of the shaded region shown on the picture. $$ A=A_{\vartriangle}-A_{i}=\dfrac{6^{2}\sqrt{3}}{4}-\dfrac{\left(3\sqrt{3}\right)^{2}\pi \cdot 60^{\circ}}{360^{\circ}}=\dfrac{36\sqrt{3}}{4}-\dfrac{9\cdot 3\cdot \pi}{6}=9\cdot \left(\sqrt{3}-\dfrac{\pi}{2}\right)cm^{2}$$
Question 5:
2 pts
Find the perimeter of the shaded figure shown on the picture.
$P=$
$8\cdot(1+\pi)cm$
$4\cdot(2+3\pi)cm$
$8\cdot(2+\pi)cm$
$6\cdot(2+2\pi)cm$
Question 6:
2 pts
Find the area of the shaded figure shown on the picture.
$A=\left(25-\dfrac{25\pi}{3}\right) cm^{2}$
$A=\left(50-\dfrac{\pi}{4}\right) cm^{2}$
$A=\left(75-\dfrac{25\pi}{4}\right) cm^{2}$
$A=\left(100-\dfrac{25\pi}{2}\right) cm^{2}$
Question 7:
2 pts
Find the area of the shaded figure shown on the picture.
$A=72cm^{2}$
$A=72\pi cm^{2}$
$A=36cm^{2}$
$A=36\pi cm^{2}$
Question 8:
2 pts
Find the length of the broken line shown on the picture.
Length of the broken line $=$
$8\pi cm$
$16\pi cm$
$24\pi cm$
$32\pi cm$
Question 9:
3 pts
Find the length of the broken line shown on the picture.
Length of the broken line $=$
$\dfrac{42\pi}{3}cm$
$\dfrac{44\pi}{3}cm$
$\dfrac{39\pi}{3}cm$
$\dfrac{56\pi}{3}cm$
Question 10:
3 pts
Find the area of the shaded figure shown on the picture.
$A=$
$A=\left(50-\dfrac{25\pi}{4}\right)cm^{2}$
$A=\left(25-\dfrac{25\pi}{4}\right)cm^{2}$
$A=\left(50-\dfrac{\pi}{4}\right)cm^{2}$
$A=\left(50-\dfrac{3\pi}{4}\right)cm^{2}$
Question 11:
3 pts
If the area of rectangle shown on the picture is $32 cm^{2}$ then the area of the shaded figure shown on the picture is $A=4\cdot (2+\pi) cm^{2}.$
Question 12:
3 pts
The following expression can be used to find the perimeter of shaded figure shown on the picture, if the length of the side of regular hexagon is 12cm. $P=\left (6\cdot 12+6\cdot \dfrac{6\pi \cdot 60^{\circ}}{180^{\circ}}\right)cm.$
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