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Current: Solve quadratic equations by using the square root property
•  Q1: 1 pts The equation $x^2 = 4$ has exactly one real solution.
•  Q2: 1 pts The equation $x^2 = 0$ has exactly one real solution.
•  Q3: 1 pts The equation $x^2 = -4$ has two real solutions.
•  Q4: 1 pts The equation $x^2 = 27$ cannot be solved using the square root property
•  Q5: 2 pts The solutions of the equation $4x^2=16$ are
 $x_1 = 4, x_2 =-4$ $x_1 = -2$ $x_1 =-2, x_2 =4$ $x_1 = -2, x_2 =2$
•  Q6: 2 pts The solutions of the equation $(x-2)^2=4$ are
 $x_1 = 2, x_2 =-2$ $x_1 = -2, x_2 =0$ $x_1 = 4, x_2 =0$ $x_1 = 0, x_2 =2$
•  Q7: 3 pts The solutions of the equation $x^2=-4$ are
 $x_1 = -2, x_2 =2$ $x_1 = -2, x_2 =0$ $x_1 = 2i, x_2 =2$ $x_1 = 2i, x_2 =-2i$