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Solving Quadratic Equations
Solving by square root property
Solving by square root property
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Question 1:
1 pts
The equation $x^2 = 4$ has exactly one real solution.
Question 2:
1 pts
The equation $x^2 = 0$ has exactly one real solution.
Question 3:
1 pts
The equation $x^2 = -4$ has two real solutions.
Question 4:
1 pts
The equation $x^2 = 27$ cannot be solved using the square root property
Question 5:
2 pts
The solutions of the equation $4x^2=16$ are
$x_1 = 4, x_2 =-4$
$x_1 = -2$
$x_1 =-2, x_2 =4$
$x_1 = -2, x_2 =2$
Question 6:
2 pts
The solutions of the equation $(x-2)^2=4$ are
$x_1 = 2, x_2 =-2$
$x_1 = -2, x_2 =0$
$x_1 = 4, x_2 =0$
$x_1 = 0, x_2 =2$
Question 7:
3 pts
The solutions of the equation $x^2=-4$ are
$x_1 = -2, x_2 =2$
$x_1 = -2, x_2 =0$
$x_1 = 2i, x_2 =2$
$x_1 = 2i, x_2 =-2i$
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Pre-algebra
Polynomials
Linear equations
Quadratic equations
Radicals
Exponents and Logarithms
Trigonometry
Algebra 2
Geometry
Solid Figures
Solving quadratic equations
Solving by square root
Completing the square
Quadratic formula
Graphing function and discriminant
Graphing quadratic function
Discriminant of a quadratic equation