The equation of the line passing through point $ \left(6,~-5\right) $, and point $ \left(0,~5\right) $ is:
$$ y = - \frac{ 5 }{ 3 } x + 5 $$To find equation of the line passing through points $ A(x_A,y_A) $ and $ B(x_B,y_B) $, we use formula:
$$ y - y_A~=~\frac{y_B - y_A}{x_B - x_A}(x-x_A) $$In this example we have:
$$ \begin{aligned} & \left(6,~-5\right) \implies x_A = 6 ~~\text{and}~~ y_A = -5 \\[1 em] & \left(0,~5\right) \implies x_B = 0 ~~\text{and}~~ y_B = 5 \end{aligned} $$After substituting into the formula, we obtain:
$$ \begin{aligned} y - y_A~&=~\frac{y_B - y_A}{x_B - x_A}(x - x_A) \\[1 em] y - \left(-5\right)~&=~\frac{ 5 - \left(-5\right) }{ 0 - 6 } \left( x - 6 \right) \\[1 em]y + 5 ~&=~ -\frac{ 5 }{ 3 } \left( x - 6 \right) \\[1 em]y + 5 ~&=~ -\frac{ 5 }{ 3 }x + 10 \\[1 em]y ~&=~ -\frac{ 5 }{ 3 }x + 5 \end{aligned} $$