The equation of the line passing through point $ \left(3.333,~\dfrac{ 55 }{ 2 }\right) $, and point $ \left(4.33,~20\right) $ is:
$$ x+0.1329y-6.9887=0 $$To find equation of the line passing through points $ A(x_A,y_A) $ and $ B(x_B,y_B) $, we use formula:
$$ y - y_A~=~\frac{y_B - y_A}{x_B - x_A}(x-x_A) $$In this example we have:
$$ \begin{aligned} & \left(3.333,~\dfrac{ 55 }{ 2 }\right) \implies x_A = 3.333 ~~\text{and}~~ y_A = \frac{ 55 }{ 2 } \\[1 em] & \left(4.33,~20\right) \implies x_B = 4.33 ~~\text{and}~~ y_B = 20 \end{aligned} $$After substituting into the formula, we obtain:
$$ \begin{aligned} y - y_A~&=~\frac{y_B - y_A}{x_B - x_A}(x - x_A) \\[1 em] y - \frac{ 55 }{ 2 }~&=~\frac{ 20 - \frac{ 55 }{ 2 } }{ 4.33 - 3.333 } \left( x - 3.333 \right) \\[1 em]y - \frac{ 55 }{ 2 } ~&=~ -7.5226 \left( x - 3.333 \right) \\[1 em]y - \frac{ 55 }{ 2 } ~&=~ -7.5226x + 25.0727 \\[1 em]y ~&=~ -7.5226x + 52.5727 \end{aligned} $$