The equation of the line passing through point $ \left(2.333,~20\right) $, and point $ \left(3.333,~\dfrac{ 55 }{ 2 }\right) $ is:
$$ x-0.1333y+0.3337=0 $$To find equation of the line passing through points $ A(x_A,y_A) $ and $ B(x_B,y_B) $, we use formula:
$$ y - y_A~=~\frac{y_B - y_A}{x_B - x_A}(x-x_A) $$In this example we have:
$$ \begin{aligned} & \left(2.333,~20\right) \implies x_A = 2.333 ~~\text{and}~~ y_A = 20 \\[1 em] & \left(3.333,~\dfrac{ 55 }{ 2 }\right) \implies x_B = 3.333 ~~\text{and}~~ y_B = \frac{ 55 }{ 2 } \end{aligned} $$After substituting into the formula, we obtain:
$$ \begin{aligned} y - y_A~&=~\frac{y_B - y_A}{x_B - x_A}(x - x_A) \\[1 em] y - 20~&=~\frac{ \frac{ 55 }{ 2 } - 20 }{ 3.333 - 2.333 } \left( x - 2.333 \right) \\[1 em]y - 20 ~&=~ 7.5 \left( x - 2.333 \right) \\[1 em]y - 20 ~&=~ 7.5x-17.4975 \\[1 em]y ~&=~ 7.5x + 2.5025 \end{aligned} $$