The equation of the line passing through point $ \left(0,~\dfrac{ 9 }{ 10 }\right) $, and point $ \left(61.565,~0.15\right) $ is:
$$ x+82.0867y-73.878=0 $$To find equation of the line passing through points $ A(x_A,y_A) $ and $ B(x_B,y_B) $, we use formula:
$$ y - y_A~=~\frac{y_B - y_A}{x_B - x_A}(x-x_A) $$In this example we have:
$$ \begin{aligned} & \left(0,~\dfrac{ 9 }{ 10 }\right) \implies x_A = 0 ~~\text{and}~~ y_A = \frac{ 9 }{ 10 } \\[1 em] & \left(61.565,~0.15\right) \implies x_B = 61.565 ~~\text{and}~~ y_B = 0.15 \end{aligned} $$After substituting into the formula, we obtain:
$$ \begin{aligned} y - y_A~&=~\frac{y_B - y_A}{x_B - x_A}(x - x_A) \\[1 em] y - \frac{ 9 }{ 10 }~&=~\frac{ 0.15 - \frac{ 9 }{ 10 } }{ 61.565 - 0 } \left( x - 0 \right) \\[1 em]y - \frac{ 9 }{ 10 } ~&=~ -0.0122 \left( x - 0 \right) \\[1 em]y - \frac{ 9 }{ 10 } ~&=~ -0.0122x + 0 \\[1 em]y ~&=~ -0.0122x + \frac{ 9 }{ 10 } \end{aligned} $$