Question
Answer
$$\dfrac{y}{4y+7}-\dfrac{8}{4y+7}=\dfrac{y-8}{4y+7}$$
Explanation
| $$ \begin{aligned}\frac{y}{4y+7}-\frac{8}{4y+7}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{y-8}{4y+7}\end{aligned} $$ | |
| ① | Subtract $ \dfrac{8}{4y+7} $ from $ \dfrac{y}{4y+7} $ to get $ \dfrac{ y - 8 }{ \color{blue}{ 4y+7 }}$. To subtract expressions with the same denominators, we subtract the numerators and write the result over the common denominator. $$ \begin{aligned} \frac{y}{4y+7} - \frac{8}{4y+7} & = \frac{y}{\color{blue}{4y+7}} - \frac{8}{\color{blue}{4y+7}} =\frac{ y - 8 }{ \color{blue}{ 4y+7 }} \end{aligned} $$ |
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Simplify Rational Expressions