Question
Answer
$$x+\dfrac{\dfrac{5}{7}}{4}x+\dfrac{20}{9}=\dfrac{\dfrac{33}{7}}{4}x+\dfrac{20}{9}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}x+\frac{\frac{5}{7}}{4}x+\frac{20}{9}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(1+\frac{\frac{5}{7}}{4})x+\frac{20}{9} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{4+\frac{5}{7}}{4}x+\frac{20}{9} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{\frac{33}{7}}{4}x+\frac{20}{9}\end{aligned} $$ | |
| ① | Use the distributive property. |
| ② | $$ 1+\frac{\frac{5}{7}}{4}
= 1 \cdot \color{blue}{\frac{ 4 }{ 4}} + \frac{\frac{5}{7}}{4} \cdot \color{blue}{\frac{ 1 }{ 1}}
= \frac{4+\frac{5}{7}}{4} $$ |
| ③ | Simplify numerator and denominator |
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