Tap the blue circles to see an explanation.
| $$ \begin{aligned}x-3+42 \cdot \frac{x}{7}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x-3+\frac{42x}{7} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{49x-21}{7}\end{aligned} $$ | |
| ① | Multiply $42$ by $ \dfrac{x}{7} $ to get $ \dfrac{ 42x }{ 7 } $. Step 1: Write $ 42 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 42 \cdot \frac{x}{7} & \xlongequal{\text{Step 1}} \frac{42}{\color{red}{1}} \cdot \frac{x}{7} \xlongequal{\text{Step 2}} \frac{ 42 \cdot x }{ 1 \cdot 7 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 42x }{ 7 } \end{aligned} $$ |
| ② | Add $x-3$ and $ \dfrac{42x}{7} $ to get $ \dfrac{ \color{purple}{ 49x-21 } }{ 7 }$. Step 1: Write $ x-3 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |