Tap the blue circles to see an explanation.
| $$ \begin{aligned}x^4+6 \cdot \frac{x^3}{7}x^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^4+\frac{6x^3}{7}x^3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^4+\frac{6x^6}{7} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{6x^6+7x^4}{7}\end{aligned} $$ | |
| ① | Multiply $6$ by $ \dfrac{x^3}{7} $ to get $ \dfrac{ 6x^3 }{ 7 } $. Step 1: Write $ 6 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 6 \cdot \frac{x^3}{7} & \xlongequal{\text{Step 1}} \frac{6}{\color{red}{1}} \cdot \frac{x^3}{7} \xlongequal{\text{Step 2}} \frac{ 6 \cdot x^3 }{ 1 \cdot 7 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 6x^3 }{ 7 } \end{aligned} $$ |
| ② | Multiply $ \dfrac{6x^3}{7} $ by $ x^3 $ to get $ \dfrac{ 6x^6 }{ 7 } $. Step 1: Write $ x^3 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{6x^3}{7} \cdot x^3 & \xlongequal{\text{Step 1}} \frac{6x^3}{7} \cdot \frac{x^3}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 6x^3 \cdot x^3 }{ 7 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 6x^6 }{ 7 } \end{aligned} $$ |
| ③ | Add $x^4$ and $ \dfrac{6x^6}{7} $ to get $ \dfrac{ \color{purple}{ 6x^6+7x^4 } }{ 7 }$. Step 1: Write $ x^4 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |