Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{x^3}{x}+\frac{\frac{4}{x}}{x^2}+8x+16& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x^3}{x}+\frac{4}{x^3}+8x+16 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{x^6+4x}{x^4}+8x+16 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{x^6+8x^5+4x}{x^4}+16 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{x^6+8x^5+16x^4+4x}{x^4}\end{aligned} $$ | |
| ① | Divide $ \dfrac{4}{x} $ by $ x^2 $ to get $ \dfrac{ 4 }{ x^3 } $. Step 1: To divide rational expressions, multiply the first fraction by the reciprocal of the second fraction. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{ \frac{4}{x} }{x^2} & \xlongequal{\text{Step 1}} \frac{4}{x} \cdot \frac{\color{blue}{1}}{\color{blue}{x^2}} \xlongequal{\text{Step 2}} \frac{ 4 \cdot 1 }{ x \cdot x^2 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 4 }{ x^3 } \end{aligned} $$ |
| ② | Add $ \dfrac{x^3}{x} $ and $ \dfrac{4}{x^3} $ to get $ \dfrac{ \color{purple}{ x^6+4x } }{ x^4 }$. To add raitonal expressions, both fractions must have the same denominator. |
| ③ | Add $ \dfrac{x^6+4x}{x^4} $ and $ 8x $ to get $ \dfrac{ \color{purple}{ x^6+8x^5+4x } }{ x^4 }$. Step 1: Write $ 8x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |
| ④ | Add $ \dfrac{x^6+8x^5+4x}{x^4} $ and $ 16 $ to get $ \dfrac{ \color{purple}{ x^6+8x^5+16x^4+4x } }{ x^4 }$. Step 1: Write $ 16 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |