Tap the blue circles to see an explanation.
| $$ \begin{aligned}x^2+8 \cdot \frac{x}{x^2}+8x+7& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2+\frac{8x}{x^2}+8x+7 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{x^4+8x}{x^2}+8x+7 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{x^4+8x^3+8x}{x^2}+7 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{x^4+8x^3+7x^2+8x}{x^2}\end{aligned} $$ | |
| ① | Multiply $8$ by $ \dfrac{x}{x^2} $ to get $ \dfrac{ 8x }{ x^2 } $. Step 1: Write $ 8 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 8 \cdot \frac{x}{x^2} & \xlongequal{\text{Step 1}} \frac{8}{\color{red}{1}} \cdot \frac{x}{x^2} \xlongequal{\text{Step 2}} \frac{ 8 \cdot x }{ 1 \cdot x^2 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 8x }{ x^2 } \end{aligned} $$ |
| ② | Add $x^2$ and $ \dfrac{8x}{x^2} $ to get $ \dfrac{ \color{purple}{ x^4+8x } }{ x^2 }$. Step 1: Write $ x^2 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |
| ③ | Add $ \dfrac{x^4+8x}{x^2} $ and $ 8x $ to get $ \dfrac{ \color{purple}{ x^4+8x^3+8x } }{ x^2 }$. Step 1: Write $ 8x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |
| ④ | Add $ \dfrac{x^4+8x^3+8x}{x^2} $ and $ 7 $ to get $ \dfrac{ \color{purple}{ x^4+8x^3+7x^2+8x } }{ x^2 }$. Step 1: Write $ 7 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |