Tap the blue circles to see an explanation.
| $$ \begin{aligned}x^2-\frac{4}{x^2}+3x-\frac{10}{x^2}+5x+\frac{6}{x^2}+8x+15& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x^4-4}{x^2}+3x-\frac{10}{x^2}+5x+\frac{6}{x^2}+8x+15 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{x^4+3x^3-4}{x^2}-\frac{10}{x^2}+5x+\frac{6}{x^2}+8x+15 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{x^4+3x^3-14}{x^2}+5x+\frac{6}{x^2}+8x+15 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{x^4+8x^3-14}{x^2}+\frac{6}{x^2}+8x+15 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle5}{\textcircled {5}} } }}}\frac{x^4+8x^3-8}{x^2}+8x+15 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle6}{\textcircled {6}} } }}}\frac{x^4+16x^3-8}{x^2}+15 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle7}{\textcircled {7}} } }}}\frac{x^4+16x^3+15x^2-8}{x^2}\end{aligned} $$ | |
| ① | Subtract $ \dfrac{4}{x^2} $ from $ x^2 $ to get $ \dfrac{ \color{purple}{ x^4-4 } }{ x^2 }$. Step 1: Write $ x^2 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To subtract raitonal expressions, both fractions must have the same denominator. |
| ② | Add $ \dfrac{x^4-4}{x^2} $ and $ 3x $ to get $ \dfrac{ \color{purple}{ x^4+3x^3-4 } }{ x^2 }$. Step 1: Write $ 3x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |
| ③ | Subtract $ \dfrac{10}{x^2} $ from $ \dfrac{x^4+3x^3-4}{x^2} $ to get $ \dfrac{x^4+3x^3-14}{x^2} $. To subtract expressions with the same denominators, we subtract the numerators and write the result over the common denominator. $$ \begin{aligned} \frac{x^4+3x^3-4}{x^2} - \frac{10}{x^2} & = \frac{x^4+3x^3-4}{\color{blue}{x^2}} - \frac{10}{\color{blue}{x^2}} = \\[1ex] &=\frac{ x^4+3x^3-4 - 10 }{ \color{blue}{ x^2 }}= \frac{x^4+3x^3-14}{x^2} \end{aligned} $$ |
| ④ | Add $ \dfrac{x^4+3x^3-14}{x^2} $ and $ 5x $ to get $ \dfrac{ \color{purple}{ x^4+8x^3-14 } }{ x^2 }$. Step 1: Write $ 5x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |
| ⑤ | Add $ \dfrac{x^4+8x^3-14}{x^2} $ and $ \dfrac{6}{x^2} $ to get $ \dfrac{x^4+8x^3-8}{x^2} $. To add expressions with the same denominators, we add the numerators and write the result over the common denominator. $$ \begin{aligned} \frac{x^4+8x^3-14}{x^2} + \frac{6}{x^2} & = \frac{x^4+8x^3-14}{\color{blue}{x^2}} + \frac{6}{\color{blue}{x^2}} = \\[1ex] &=\frac{ x^4+8x^3-14 + 6 }{ \color{blue}{ x^2 }}= \frac{x^4+8x^3-8}{x^2} \end{aligned} $$ |
| ⑥ | Add $ \dfrac{x^4+8x^3-8}{x^2} $ and $ 8x $ to get $ \dfrac{ \color{purple}{ x^4+16x^3-8 } }{ x^2 }$. Step 1: Write $ 8x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |
| ⑦ | Add $ \dfrac{x^4+16x^3-8}{x^2} $ and $ 15 $ to get $ \dfrac{ \color{purple}{ x^4+16x^3+15x^2-8 } }{ x^2 }$. Step 1: Write $ 15 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |