Question
Answer
$$x^2-\dfrac{36}{2}x^3+12x^2=-18x^3+13x^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}x^2-\frac{36}{2}x^3+12x^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2 - \frac{ 36 : \color{orangered}{ 2 } }{ 2 : \color{orangered}{ 2 }} \cdot x^3 + 12x^2 \xlongequal{ } \\[1 em] & \xlongequal{ }x^2-\frac{18}{1}x^3+12x^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2-18x^3+12x^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-18x^3+13x^2\end{aligned} $$ | |
| ① | Divide both the top and bottom numbers by $ \color{orangered}{ 2 } $. |
| ② | Remove 1 from denominator. |
| ③ | Combine like terms: $$ \color{blue}{x^2} -18x^3+ \color{blue}{12x^2} = -18x^3+ \color{blue}{13x^2} $$ |
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