Tap the blue circles to see an explanation.
| $$ \begin{aligned}x^2-\frac{2}{12}+\frac{x}{6}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2 - \frac{ 2 : \color{orangered}{ 2 } }{ 12 : \color{orangered}{ 2 }} + \frac{x}{6} \xlongequal{ } \\[1 em] & \xlongequal{ }x^2-\frac{1}{6}+\frac{x}{6} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{6x^2-1}{6}+\frac{x}{6} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{6x^2+x-1}{6}\end{aligned} $$ | |
| ① | Divide both the top and bottom numbers by $ \color{orangered}{ 2 } $. |
| ② | Subtract $ \dfrac{1}{6} $ from $ x^2 $ to get $ \dfrac{ \color{purple}{ 6x^2-1 } }{ 6 }$. Step 1: Write $ x^2 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To subtract raitonal expressions, both fractions must have the same denominator. |
| ③ | Add $ \dfrac{6x^2-1}{6} $ and $ \dfrac{x}{6} $ to get $ \dfrac{6x^2+x-1}{6} $. To add expressions with the same denominators, we add the numerators and write the result over the common denominator. $$ \begin{aligned} \frac{6x^2-1}{6} + \frac{x}{6} & = \frac{6x^2-1}{\color{blue}{6}} + \frac{x}{\color{blue}{6}} =\frac{ 6x^2-1 + x }{ \color{blue}{ 6 }} = \\[1ex] &= \frac{6x^2+x-1}{6} \end{aligned} $$ |