Question
Answer
$$x^2-12x+\dfrac{36}{4}x-24=x^2-3x-24$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}x^2-12x+\frac{36}{4}x-24& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2-12x + \frac{ 36 : \color{orangered}{ 4 } }{ 4 : \color{orangered}{ 4 }} \cdot x - 24 \xlongequal{ } \\[1 em] & \xlongequal{ }x^2-12x+\frac{9}{1}x-24 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2-12x+9x-24 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}x^2-3x-24\end{aligned} $$ | |
| ① | Divide both the top and bottom numbers by $ \color{orangered}{ 4 } $. |
| ② | Remove 1 from denominator. |
| ③ | Combine like terms: $$ x^2 \color{blue}{-12x} + \color{blue}{9x} -24 = x^2 \color{blue}{-3x} -24 $$ |
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