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Question

Answer

$$\dfrac{x}{9}-\dfrac{1}{3}=\dfrac{x-3}{9}$$

Explanation
$$ \begin{aligned}\frac{x}{9}-\frac{1}{3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x-3}{9}\end{aligned} $$
①

Subtract $ \dfrac{1}{3} $ from $ \dfrac{x}{9} $ to get $ \dfrac{ \color{purple}{ x-3 } }{ 9 }$.

To subtract raitonal expressions, both fractions must have the same denominator.
We can create a common denominator by multiplying the second fraction by $\color{blue}{3}$.

$$ \begin{aligned} \frac{x}{9} - \frac{1}{3} & = \frac{ x }{ 9 } - \frac{ 1 \cdot \color{blue}{ 3 }}{ 3 \cdot \color{blue}{ 3 }} = \\[1ex] &=\frac{ \color{purple}{ x } }{ 9 } - \frac{ \color{purple}{ 3 } }{ 9 }=\frac{ \color{purple}{ x-3 } }{ 9 } \end{aligned} $$
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