Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{x}{2^2}-x& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(\frac{1}{2^2}-1)x \xlongequal{ } \\[1 em] & \xlongequal{ }(\frac{1}{4}-1)x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}(-\frac{3}{4})x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-\frac{3x}{4}\end{aligned} $$ | |
| ① | Use the distributive property. |
| ② | Subtract $1$ from $ \dfrac{1}{4} $ to get $ \dfrac{ \color{purple}{ -3 } }{ 4 }$. Step 1: Write $ 1 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To subtract fractions they must have the same denominator. |
| ③ | Multiply $ \dfrac{-3}{4} $ by $ x $ to get $ \dfrac{ -3x }{ 4 } $. Step 1: Write $ x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{-3}{4} \cdot x & \xlongequal{\text{Step 1}} \frac{-3}{4} \cdot \frac{x}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ \left( -3 \right) \cdot x }{ 4 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ -3x }{ 4 } \end{aligned} $$ |