Question
Answer
$$r(4+6+2+1)=r\cdot13$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}r(4+6+2+1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}r\cdot(10+3) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}r\cdot13\end{aligned} $$ | |
| ① | Combine like terms: $$ \color{blue}{4} + \color{blue}{6} = \color{blue}{10} $$Combine like terms: $$ \color{blue}{2} + \color{blue}{1} = \color{blue}{3} $$ |
| ② | Combine like terms: $$ \color{blue}{10} + \color{blue}{3} = \color{blue}{13} $$ |
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