Question
Answer
$$9x^5 \cdot \dfrac{y^2}{15xy^3}=\dfrac{9x^5y^2}{15xy^3}$$
Explanation
| $$ \begin{aligned}9x^5\frac{y^2}{15xy^3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{9x^5y^2}{15xy^3}\end{aligned} $$ | |
| ① | Multiply $9x^5$ by $ \dfrac{y^2}{15xy^3} $ to get $ \dfrac{ 9x^5y^2 }{ 15xy^3 } $. Step 1: Write $ 9x^5 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 9x^5 \cdot \frac{y^2}{15xy^3} & \xlongequal{\text{Step 1}} \frac{9x^5}{\color{red}{1}} \cdot \frac{y^2}{15xy^3} \xlongequal{\text{Step 2}} \frac{ 9x^5 \cdot y^2 }{ 1 \cdot 15xy^3 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 9x^5y^2 }{ 15xy^3 } \end{aligned} $$ |
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