Question
Answer
$$9\cdot\dfrac{x^2}{36x^2-180x}=\dfrac{9x^2}{36x^2-180x}$$
Explanation
| $$ \begin{aligned}9 \cdot \frac{x^2}{36x^2-180x}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{9x^2}{36x^2-180x}\end{aligned} $$ | |
| ① | Multiply $9$ by $ \dfrac{x^2}{36x^2-180x} $ to get $ \dfrac{ 9x^2 }{ 36x^2-180x } $. Step 1: Write $ 9 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 9 \cdot \frac{x^2}{36x^2-180x} & \xlongequal{\text{Step 1}} \frac{9}{\color{red}{1}} \cdot \frac{x^2}{36x^2-180x} \xlongequal{\text{Step 2}} \frac{ 9 \cdot x^2 }{ 1 \cdot \left( 36x^2-180x \right) } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 9x^2 }{ 36x^2-180x } \end{aligned} $$ |
This page was created using
Simplify Rational Expressions