Tap the blue circles to see an explanation.
| $$ \begin{aligned}8x-16 \cdot \frac{x^2}{8}x& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(8-16 \cdot \frac{x^2}{8})x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}(8-\frac{16x^2}{8})x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{-16x^2+64}{8}x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{-16x^3+64x}{8}\end{aligned} $$ | |
| ① | Use the distributive property. |
| ② | Multiply $16$ by $ \dfrac{x^2}{8} $ to get $ \dfrac{ 16x^2 }{ 8 } $. Step 1: Write $ 16 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 16 \cdot \frac{x^2}{8} & \xlongequal{\text{Step 1}} \frac{16}{\color{red}{1}} \cdot \frac{x^2}{8} \xlongequal{\text{Step 2}} \frac{ 16 \cdot x^2 }{ 1 \cdot 8 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 16x^2 }{ 8 } \end{aligned} $$ |
| ③ | Subtract $ \dfrac{16x^2}{8} $ from $ 8 $ to get $ \dfrac{ \color{purple}{ -16x^2+64 } }{ 8 }$. Step 1: Write $ 8 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To subtract raitonal expressions, both fractions must have the same denominator. |
| ④ | Multiply $ \dfrac{-16x^2+64}{8} $ by $ x $ to get $ \dfrac{ -16x^3+64x }{ 8 } $. Step 1: Write $ x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{-16x^2+64}{8} \cdot x & \xlongequal{\text{Step 1}} \frac{-16x^2+64}{8} \cdot \frac{x}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ \left( -16x^2+64 \right) \cdot x }{ 8 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ -16x^3+64x }{ 8 } \end{aligned} $$ |