Question
Answer
$$8\cdot\dfrac{x}{4-8x}=\dfrac{8x}{-8x+4}$$
Explanation
| $$ \begin{aligned}8 \cdot \frac{x}{4-8x}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{8x}{-8x+4}\end{aligned} $$ | |
| ① | Multiply $8$ by $ \dfrac{x}{4-8x} $ to get $ \dfrac{8x}{-8x+4} $. Step 1: Write $ 8 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 8 \cdot \frac{x}{4-8x} & \xlongequal{\text{Step 1}} \frac{8}{\color{red}{1}} \cdot \frac{x}{4-8x} \xlongequal{\text{Step 2}} \frac{ 8 \cdot x }{ 1 \cdot \left( 4-8x \right) } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 8x }{ 4-8x } = \frac{8x}{-8x+4} \end{aligned} $$ |
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Simplify Rational Expressions