Question
Answer
$$72x^8 \cdot \dfrac{y^7}{64x^5y^4}=\dfrac{72x^8y^7}{64x^5y^4}$$
Explanation
| $$ \begin{aligned}72x^8\frac{y^7}{64x^5y^4}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{72x^8y^7}{64x^5y^4}\end{aligned} $$ | |
| ① | Multiply $72x^8$ by $ \dfrac{y^7}{64x^5y^4} $ to get $ \dfrac{ 72x^8y^7 }{ 64x^5y^4 } $. Step 1: Write $ 72x^8 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 72x^8 \cdot \frac{y^7}{64x^5y^4} & \xlongequal{\text{Step 1}} \frac{72x^8}{\color{red}{1}} \cdot \frac{y^7}{64x^5y^4} \xlongequal{\text{Step 2}} \frac{ 72x^8 \cdot y^7 }{ 1 \cdot 64x^5y^4 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 72x^8y^7 }{ 64x^5y^4 } \end{aligned} $$ |
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