| $$ \begin{aligned}\frac{7}{3}-\frac{8}{12x-8}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{84x-80}{36x-24} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{21x-20}{9x-6}\end{aligned} $$ | |
| ① | Subtract $ \dfrac{8}{12x-8} $ from $ \dfrac{7}{3} $ to get $ \dfrac{ \color{purple}{ 84x-80 } }{ 36x-24 }$. To subtract raitonal expressions, both fractions must have the same denominator. |