Tap the blue circles to see an explanation.
| $$ \begin{aligned}6 \cdot \frac{x^3}{12}x^2-72x& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{6x^3}{12}x^2-72x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{6x^5}{12}-72x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{6x^5-864x}{12}\end{aligned} $$ | |
| ① | Multiply $6$ by $ \dfrac{x^3}{12} $ to get $ \dfrac{ 6x^3 }{ 12 } $. Step 1: Write $ 6 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 6 \cdot \frac{x^3}{12} & \xlongequal{\text{Step 1}} \frac{6}{\color{red}{1}} \cdot \frac{x^3}{12} \xlongequal{\text{Step 2}} \frac{ 6 \cdot x^3 }{ 1 \cdot 12 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 6x^3 }{ 12 } \end{aligned} $$ |
| ② | Multiply $ \dfrac{6x^3}{12} $ by $ x^2 $ to get $ \dfrac{ 6x^5 }{ 12 } $. Step 1: Write $ x^2 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{6x^3}{12} \cdot x^2 & \xlongequal{\text{Step 1}} \frac{6x^3}{12} \cdot \frac{x^2}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 6x^3 \cdot x^2 }{ 12 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 6x^5 }{ 12 } \end{aligned} $$ |
| ③ | Subtract $72x$ from $ \dfrac{6x^5}{12} $ to get $ \dfrac{ \color{purple}{ 6x^5-864x } }{ 12 }$. Step 1: Write $ 72x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To subtract raitonal expressions, both fractions must have the same denominator. |