Question
Answer
$$6\cdot\dfrac{x^3}{x^2+3x}=\dfrac{6x^3}{x^2+3x}$$
Explanation
| $$ \begin{aligned}6 \cdot \frac{x^3}{x^2+3x}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{6x^3}{x^2+3x}\end{aligned} $$ | |
| ① | Multiply $6$ by $ \dfrac{x^3}{x^2+3x} $ to get $ \dfrac{ 6x^3 }{ x^2+3x } $. Step 1: Write $ 6 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 6 \cdot \frac{x^3}{x^2+3x} & \xlongequal{\text{Step 1}} \frac{6}{\color{red}{1}} \cdot \frac{x^3}{x^2+3x} \xlongequal{\text{Step 2}} \frac{ 6 \cdot x^3 }{ 1 \cdot \left( x^2+3x \right) } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 6x^3 }{ x^2+3x } \end{aligned} $$ |
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