Tap the blue circles to see an explanation.
| $$ \begin{aligned}6x^2+13x-\frac{5}{6}x^2-23x+7& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^2+13x-\frac{5x^2}{6}-23x+7 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{31x^2+78x}{6}-23x+7 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{31x^2-60x}{6}+7 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{31x^2-60x+42}{6}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{5}{6} $ by $ x^2 $ to get $ \dfrac{ 5x^2 }{ 6 } $. Step 1: Write $ x^2 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{5}{6} \cdot x^2 & \xlongequal{\text{Step 1}} \frac{5}{6} \cdot \frac{x^2}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 5 \cdot x^2 }{ 6 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 5x^2 }{ 6 } \end{aligned} $$ |
| ② | Subtract $ \dfrac{5x^2}{6} $ from $ 6x^2+13x $ to get $ \dfrac{ \color{purple}{ 31x^2+78x } }{ 6 }$. Step 1: Write $ 6x^2+13x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To subtract raitonal expressions, both fractions must have the same denominator. |
| ③ | Subtract $23x$ from $ \dfrac{31x^2+78x}{6} $ to get $ \dfrac{ \color{purple}{ 31x^2-60x } }{ 6 }$. Step 1: Write $ 23x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To subtract raitonal expressions, both fractions must have the same denominator. |
| ④ | Add $ \dfrac{31x^2-60x}{6} $ and $ 7 $ to get $ \dfrac{ \color{purple}{ 31x^2-60x+42 } }{ 6 }$. Step 1: Write $ 7 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |