Question
Answer
$$5\cdot\dfrac{x^2}{7}\cdot\dfrac{8}{9x^2}=\dfrac{40x^2}{63x^2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}5 \cdot \frac{x^2}{7}\cdot\frac{8}{9x^2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{5x^2}{7}\cdot\frac{8}{9x^2} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{40x^2}{63x^2}\end{aligned} $$ | |
| ① | Multiply $5$ by $ \dfrac{x^2}{7} $ to get $ \dfrac{ 5x^2 }{ 7 } $. Step 1: Write $ 5 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 5 \cdot \frac{x^2}{7} & \xlongequal{\text{Step 1}} \frac{5}{\color{red}{1}} \cdot \frac{x^2}{7} \xlongequal{\text{Step 2}} \frac{ 5 \cdot x^2 }{ 1 \cdot 7 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 5x^2 }{ 7 } \end{aligned} $$ |
| ② | Multiply $ \dfrac{5x^2}{7} $ by $ \dfrac{8}{9x^2} $ to get $ \dfrac{ 40x^2 }{ 63x^2 } $. Step 1: Multiply numerators and denominators. Step 2: Simplify numerator and denominator. $$ \begin{aligned} \frac{5x^2}{7} \cdot \frac{8}{9x^2} & \xlongequal{\text{Step 1}} \frac{ 5x^2 \cdot 8 }{ 7 \cdot 9x^2 } \xlongequal{\text{Step 2}} \frac{ 40x^2 }{ 63x^2 } \end{aligned} $$ |
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