Question
Answer
$$5\cdot\dfrac{x^2}{15x^2-45x}=\dfrac{5x^2}{15x^2-45x}$$
Explanation
| $$ \begin{aligned}5 \cdot \frac{x^2}{15x^2-45x}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{5x^2}{15x^2-45x}\end{aligned} $$ | |
| ① | Multiply $5$ by $ \dfrac{x^2}{15x^2-45x} $ to get $ \dfrac{ 5x^2 }{ 15x^2-45x } $. Step 1: Write $ 5 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 5 \cdot \frac{x^2}{15x^2-45x} & \xlongequal{\text{Step 1}} \frac{5}{\color{red}{1}} \cdot \frac{x^2}{15x^2-45x} \xlongequal{\text{Step 2}} \frac{ 5 \cdot x^2 }{ 1 \cdot \left( 15x^2-45x \right) } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 5x^2 }{ 15x^2-45x } \end{aligned} $$ |
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