Multiply $5$ by $ \dfrac{x}{x^2} $ to get $ \dfrac{ 5x }{ x^2 } $.

Step 1: Write $ 5 $ as a fraction by putting $ \color{red}{1} $ in the denominator.

Step 2: Multiply numerators and denominators.

Step 3: Simplify numerator and denominator.

$$ \begin{aligned} 5 \cdot \frac{x}{x^2} & \xlongequal{\text{Step 1}} \frac{5}{\color{red}{1}} \cdot \frac{x}{x^2} \xlongequal{\text{Step 2}} \frac{ 5 \cdot x }{ 1 \cdot x^2 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 5x }{ x^2 } \end{aligned} $$

Subtract $24x$ from $ \dfrac{5x}{x^2} $ to get $ \dfrac{ \color{purple}{ -24x^3+5x } }{ x^2 }$.

Step 1: Write $ 24x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator.

Step 2: To subtract raitonal expressions, both fractions must have the same denominator.
We can create a common denominator by multiplying the second fraction by $\color{blue}{x^2}$.

$$ \begin{aligned} \frac{5x}{x^2} -24x & \xlongequal{\text{Step 1}} \frac{5x}{x^2} - \frac{24x}{\color{red}{1}} = \frac{ 5x }{ x^2 } - \frac{ 24x \cdot \color{blue}{ x^2 }}{ 1 \cdot \color{blue}{ x^2 }} = \\[1ex] & \xlongequal{\text{Step 2}} \frac{ \color{purple}{ 5x } }{ x^2 } - \frac{ \color{purple}{ 24x^3 } }{ x^2 }=\frac{ \color{purple}{ -24x^3+5x } }{ x^2 } \end{aligned} $$

Subtract $25$ from $ \dfrac{-24x^3+5x}{x^2} $ to get $ \dfrac{ \color{purple}{ -24x^3-25x^2+5x } }{ x^2 }$.

Step 1: Write $ 25 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator.

Step 2: To subtract raitonal expressions, both fractions must have the same denominator.
We can create a common denominator by multiplying the second fraction by $\color{blue}{x^2}$.

$$ \begin{aligned} \frac{-24x^3+5x}{x^2} -25 & \xlongequal{\text{Step 1}} \frac{-24x^3+5x}{x^2} - \frac{25}{\color{red}{1}} = \frac{ -24x^3+5x }{ x^2 } - \frac{ 25 \cdot \color{blue}{ x^2 }}{ 1 \cdot \color{blue}{ x^2 }} = \\[1ex] & \xlongequal{\text{Step 2}} \frac{ \color{purple}{ -24x^3+5x } }{ x^2 } - \frac{ \color{purple}{ 25x^2 } }{ x^2 }=\frac{ \color{purple}{ -24x^3-25x^2+5x } }{ x^2 } \end{aligned} $$