Tap the blue circles to see an explanation.
| $$ \begin{aligned}5 \cdot \frac{x}{4}x^3-2\frac{x}{4x+6}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{5x}{4}x^3-\frac{2x}{4x+6} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{5x^4}{4}-\frac{2x}{4x+6} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle5}{\textcircled {5}} } }}}\frac{20x^5+30x^4-8x}{16x+24} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{10x^5+15x^4-4x}{8x+12}\end{aligned} $$ | |
| ① | Multiply $5$ by $ \dfrac{x}{4} $ to get $ \dfrac{ 5x }{ 4 } $. Step 1: Write $ 5 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 5 \cdot \frac{x}{4} & \xlongequal{\text{Step 1}} \frac{5}{\color{red}{1}} \cdot \frac{x}{4} \xlongequal{\text{Step 2}} \frac{ 5 \cdot x }{ 1 \cdot 4 } \xlongequal{\text{Step 3}} \frac{ 5x }{ 4 } \end{aligned} $$ |
| ② | Multiply $2$ by $ \dfrac{x}{4x+6} $ to get $ \dfrac{ 2x }{ 4x+6 } $. Step 1: Write $ 2 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 2 \cdot \frac{x}{4x+6} & \xlongequal{\text{Step 1}} \frac{2}{\color{red}{1}} \cdot \frac{x}{4x+6} \xlongequal{\text{Step 2}} \frac{ 2 \cdot x }{ 1 \cdot \left( 4x+6 \right) } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 2x }{ 4x+6 } \end{aligned} $$ |
| ③ | Multiply $ \dfrac{5x}{4} $ by $ x^3 $ to get $ \dfrac{ 5x^4 }{ 4 } $. Step 1: Write $ x^3 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{5x}{4} \cdot x^3 & \xlongequal{\text{Step 1}} \frac{5x}{4} \cdot \frac{x^3}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 5x \cdot x^3 }{ 4 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 5x^4 }{ 4 } \end{aligned} $$ |
| ④ | Multiply $2$ by $ \dfrac{x}{4x+6} $ to get $ \dfrac{ 2x }{ 4x+6 } $. Step 1: Write $ 2 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 2 \cdot \frac{x}{4x+6} & \xlongequal{\text{Step 1}} \frac{2}{\color{red}{1}} \cdot \frac{x}{4x+6} \xlongequal{\text{Step 2}} \frac{ 2 \cdot x }{ 1 \cdot \left( 4x+6 \right) } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 2x }{ 4x+6 } \end{aligned} $$ |
| ⑤ | Subtract $ \dfrac{2x}{4x+6} $ from $ \dfrac{5x^4}{4} $ to get $ \dfrac{ \color{purple}{ 20x^5+30x^4-8x } }{ 16x+24 }$. To subtract raitonal expressions, both fractions must have the same denominator. |