| $$ \begin{aligned}5 \cdot \frac{x}{x-2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{5x}{x-2}\end{aligned} $$ | |
| ① | Multiply $5$ by $ \dfrac{x}{x-2} $ to get $ \dfrac{ 5x }{ x-2 } $. Step 1: Write $ 5 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 5 \cdot \frac{x}{x-2} & \xlongequal{\text{Step 1}} \frac{5}{\color{red}{1}} \cdot \frac{x}{x-2} \xlongequal{\text{Step 2}} \frac{ 5 \cdot x }{ 1 \cdot \left( x-2 \right) } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 5x }{ x-2 } \end{aligned} $$ |