Question
Answer
$$5+(1-4x)(x+3)=-4x^2-11x+8$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}5+(1-4x)(x+3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}5+x+3-4x^2-12x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}5-4x^2-11x+3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-4x^2-11x+8\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{1-4x}\right) $ by each term in $ \left( x+3\right) $. $$ \left( \color{blue}{1-4x}\right) \cdot \left( x+3\right) = x+3-4x^2-12x $$ |
| ② | Combine like terms: $$ \color{blue}{x} +3-4x^2 \color{blue}{-12x} = -4x^2 \color{blue}{-11x} +3 $$ |
| ③ | Combine like terms: $$ \color{blue}{5} -4x^2-11x+ \color{blue}{3} = -4x^2-11x+ \color{blue}{8} $$ |
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