Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{5}{4}x^3y+\frac{1}{6}xy^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{5x^3}{4}y+\frac{x}{6}y^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{5x^3y}{4}+\frac{xy^2}{6} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle5}{\textcircled {5}} } }}}\frac{15x^3y+2xy^2}{12}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{5}{4} $ by $ x^3 $ to get $ \dfrac{ 5x^3 }{ 4 } $. Step 1: Write $ x^3 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{5}{4} \cdot x^3 & \xlongequal{\text{Step 1}} \frac{5}{4} \cdot \frac{x^3}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 5 \cdot x^3 }{ 4 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 5x^3 }{ 4 } \end{aligned} $$ |
| ② | Multiply $ \dfrac{1}{6} $ by $ x $ to get $ \dfrac{ x }{ 6 } $. Step 1: Write $ x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{1}{6} \cdot x & \xlongequal{\text{Step 1}} \frac{1}{6} \cdot \frac{x}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 1 \cdot x }{ 6 \cdot 1 } \xlongequal{\text{Step 3}} \frac{ x }{ 6 } \end{aligned} $$ |
| ③ | Multiply $ \dfrac{5x^3}{4} $ by $ y $ to get $ \dfrac{ 5x^3y }{ 4 } $. Step 1: Write $ y $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{5x^3}{4} \cdot y & \xlongequal{\text{Step 1}} \frac{5x^3}{4} \cdot \frac{y}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 5x^3 \cdot y }{ 4 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 5x^3y }{ 4 } \end{aligned} $$ |
| ④ | Multiply $ \dfrac{x}{6} $ by $ y^2 $ to get $ \dfrac{ xy^2 }{ 6 } $. Step 1: Write $ y^2 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{x}{6} \cdot y^2 & \xlongequal{\text{Step 1}} \frac{x}{6} \cdot \frac{y^2}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ x \cdot y^2 }{ 6 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ xy^2 }{ 6 } \end{aligned} $$ |
| ⑤ | Add $ \dfrac{5x^3y}{4} $ and $ \dfrac{xy^2}{6} $ to get $ \dfrac{ \color{purple}{ 15x^3y+2xy^2 } }{ 12 }$. To add raitonal expressions, both fractions must have the same denominator. |