Question
Answer
$$5(v+1)(-v+8)=-5v^2+35v+40$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}5(v+1)(-v+8)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(5v+5)(-v+8) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-5v^2+40v-5v+40 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-5v^2+35v+40\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{5} $ by $ \left( v+1\right) $ $$ \color{blue}{5} \cdot \left( v+1\right) = 5v+5 $$ |
| ② | Multiply each term of $ \left( \color{blue}{5v+5}\right) $ by each term in $ \left( -v+8\right) $. $$ \left( \color{blue}{5v+5}\right) \cdot \left( -v+8\right) = -5v^2+40v-5v+40 $$ |
| ③ | Combine like terms: $$ -5v^2+ \color{blue}{40v} \color{blue}{-5v} +40 = -5v^2+ \color{blue}{35v} +40 $$ |
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