Question
Answer
$$5(2x+3)-4(x-2)=6x+23$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}5(2x+3)-4(x-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}10x+15-(4x-8) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}10x+15-4x+8 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}6x+23\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{5} $ by $ \left( 2x+3\right) $ $$ \color{blue}{5} \cdot \left( 2x+3\right) = 10x+15 $$Multiply $ \color{blue}{4} $ by $ \left( x-2\right) $ $$ \color{blue}{4} \cdot \left( x-2\right) = 4x-8 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left( 4x-8 \right) = -4x+8 $$ |
| ③ | Combine like terms: $$ \color{blue}{10x} + \color{red}{15} \color{blue}{-4x} + \color{red}{8} = \color{blue}{6x} + \color{red}{23} $$ |
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