Tap the blue circles to see an explanation.
| $$ \begin{aligned}4x-\frac{4}{6}x-20& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(4-\frac{4}{6})x-20 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{10}{3}x-20 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{10x}{3}-20 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{10x-60}{3}\end{aligned} $$ | |
| ① | Use the distributive property. |
| ② | Combine like terms |
| ③ | Multiply $ \dfrac{10}{3} $ by $ x $ to get $ \dfrac{ 10x }{ 3 } $. Step 1: Write $ x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{10}{3} \cdot x & \xlongequal{\text{Step 1}} \frac{10}{3} \cdot \frac{x}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 10 \cdot x }{ 3 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 10x }{ 3 } \end{aligned} $$ |
| ④ | Subtract $20$ from $ \dfrac{10x}{3} $ to get $ \dfrac{ \color{purple}{ 10x-60 } }{ 3 }$. Step 1: Write $ 20 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To subtract raitonal expressions, both fractions must have the same denominator. |