Tap the blue circles to see an explanation.
| $$ \begin{aligned}4x-\frac{1}{4}x-3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(4-\frac{1}{4})x-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{15}{4}x-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{15x}{4}-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{15x-12}{4}\end{aligned} $$ | |
| ① | Use the distributive property. |
| ② | Combine like terms |
| ③ | Multiply $ \dfrac{15}{4} $ by $ x $ to get $ \dfrac{ 15x }{ 4 } $. Step 1: Write $ x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{15}{4} \cdot x & \xlongequal{\text{Step 1}} \frac{15}{4} \cdot \frac{x}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 15 \cdot x }{ 4 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 15x }{ 4 } \end{aligned} $$ |
| ④ | Subtract $3$ from $ \dfrac{15x}{4} $ to get $ \dfrac{ \color{purple}{ 15x-12 } }{ 4 }$. Step 1: Write $ 3 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To subtract raitonal expressions, both fractions must have the same denominator. |