Tap the blue circles to see an explanation.
| $$ \begin{aligned}4x-\frac{1}{2}x+3-7x-\frac{4}{2}x+3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}(4-\frac{1}{2})x+3-7x - \frac{ 4 : \color{orangered}{ 2 } }{ 2 : \color{orangered}{ 2 }} \cdot x + 3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{7}{2}x+3-7x-\frac{2}{1}x+3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} \htmlClass{explanationCircle explanationCircle5}{\textcircled {5}} } }}}\frac{7x}{2}+3-7x-2x+3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle6}{\textcircled {6}} \htmlClass{explanationCircle explanationCircle7}{\textcircled {7}} } }}}\frac{7x+6}{2}-7x-2x+3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle8}{\textcircled {8}} \htmlClass{explanationCircle explanationCircle9}{\textcircled {9}} } }}}\frac{-7x+6}{2}-2x+3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle10}{\textcircled {10}} } }}}\frac{-11x+6}{2}+3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle11}{\textcircled {11}} } }}}\frac{-11x+12}{2}\end{aligned} $$ | |
| ① | Use the distributive property. |
| ② | Divide both the top and bottom numbers by $ \color{orangered}{ 2 } $. |
| ③ | Combine like terms |
| ④ | Multiply $ \dfrac{7}{2} $ by $ x $ to get $ \dfrac{ 7x }{ 2 } $. Step 1: Write $ x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{7}{2} \cdot x & \xlongequal{\text{Step 1}} \frac{7}{2} \cdot \frac{x}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 7 \cdot x }{ 2 \cdot 1 } \xlongequal{\text{Step 3}} \frac{ 7x }{ 2 } \end{aligned} $$ |
| ⑤ | Remove 1 from denominator. |
| ⑥ | Add $ \dfrac{7x}{2} $ and $ 3 $ to get $ \dfrac{ \color{purple}{ 7x+6 } }{ 2 }$. Step 1: Write $ 3 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |
| ⑦ | Remove 1 from denominator. |
| ⑧ | Subtract $7x$ from $ \dfrac{7x+6}{2} $ to get $ \dfrac{ \color{purple}{ -7x+6 } }{ 2 }$. Step 1: Write $ 7x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To subtract raitonal expressions, both fractions must have the same denominator. |
| ⑨ | Remove 1 from denominator. |
| ⑩ | Subtract $2x$ from $ \dfrac{-7x+6}{2} $ to get $ \dfrac{ \color{purple}{ -11x+6 } }{ 2 }$. Step 1: Write $ 2x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To subtract raitonal expressions, both fractions must have the same denominator. |
| ⑪ | Add $ \dfrac{-11x+6}{2} $ and $ 3 $ to get $ \dfrac{ \color{purple}{ -11x+12 } }{ 2 }$. Step 1: Write $ 3 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |