Question
Answer
$$4x^2-17x+\dfrac{4}{4}x^2+19x-5=5x^2+2x-5$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}4x^2-17x+\frac{4}{4}x^2+19x-5& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4x^2-17x + \frac{ 4 : \color{orangered}{ 4 } }{ 4 : \color{orangered}{ 4 }} \cdot x^2 + 19x - 5 \xlongequal{ } \\[1 em] & \xlongequal{ }4x^2-17x+\frac{1}{1}x^2+19x-5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4x^2-17x+x^2+19x-5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}5x^2-17x+19x-5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}5x^2+2x-5\end{aligned} $$ | |
| ① | Divide both the top and bottom numbers by $ \color{orangered}{ 4 } $. |
| ② | Remove 1 from denominator. |
| ③ | Combine like terms: $$ \color{blue}{4x^2} -17x+ \color{blue}{x^2} = \color{blue}{5x^2} -17x $$ |
| ④ | Combine like terms: $$ 5x^2 \color{blue}{-17x} + \color{blue}{19x} -5 = 5x^2+ \color{blue}{2x} -5 $$ |
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