Question
Answer
$$40x^2 \cdot \dfrac{y}{4xy+12y^2}=\dfrac{40x^2y}{4xy+12y^2}$$
Explanation
| $$ \begin{aligned}40x^2\frac{y}{4xy+12y^2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{40x^2y}{4xy+12y^2}\end{aligned} $$ | |
| ① | Multiply $40x^2$ by $ \dfrac{y}{4xy+12y^2} $ to get $ \dfrac{ 40x^2y }{ 4xy+12y^2 } $. Step 1: Write $ 40x^2 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 40x^2 \cdot \frac{y}{4xy+12y^2} & \xlongequal{\text{Step 1}} \frac{40x^2}{\color{red}{1}} \cdot \frac{y}{4xy+12y^2} \xlongequal{\text{Step 2}} \frac{ 40x^2 \cdot y }{ 1 \cdot \left( 4xy+12y^2 \right) } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 40x^2y }{ 4xy+12y^2 } \end{aligned} $$ |
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Simplify Rational Expressions