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Question

Answer

$$\dfrac{4}{5}+(-\dfrac{1}{10})+\dfrac{3}{5}=\dfrac{13}{10}$$

Explanation

Tap the blue circles to see an explanation.

$$ \begin{aligned}\frac{4}{5}+(-\frac{1}{10})+\frac{3}{5}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{7}{10}+\frac{3}{5} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{13}{10}\end{aligned} $$
①
Combine like terms
②

Add $ \dfrac{7}{10} $ and $ \dfrac{3}{5} $ to get $ \dfrac{ \color{purple}{ 13 } }{ 10 }$.

To add fractions they must have the same denominator.
We can create a common denominator by multiplying the second fraction by $\color{blue}{2}$.

$$ \begin{aligned} \frac{7}{10} + \frac{3}{5} & = \frac{ 7 }{ 10 } + \frac{ 3 \cdot \color{blue}{ 2 }}{ 5 \cdot \color{blue}{ 2 }} = \\[1ex] &=\frac{ \color{purple}{ 7 } }{ 10 } + \frac{ \color{purple}{ 6 } }{ 10 }=\frac{ \color{purple}{ 13 } }{ 10 } \end{aligned} $$
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