Question
Answer
$$4(b-5)-(b+1)=3b-21$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}4(b-5)-(b+1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4b-20-(b+1) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4b-20-b-1 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}3b-21\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{4} $ by $ \left( b-5\right) $ $$ \color{blue}{4} \cdot \left( b-5\right) = 4b-20 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left( b+1 \right) = -b-1 $$ |
| ③ | Combine like terms: $$ \color{blue}{4b} \color{red}{-20} \color{blue}{-b} \color{red}{-1} = \color{blue}{3b} \color{red}{-21} $$ |
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